The equations in Exercises 79–90 combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. 4/(x - 2) + 3/(x + 5) = 7/(x + 5)(x - 2)
Ch. 1 - Equations and Inequalities

2장, 문제 88
Solve each radical equation in Exercises 88–89. √ (2x-3) + x = 3
검증된 단계별 안내1
Step 1: Isolate the radical expression on one side of the equation. Subtract x from both sides to get: √(2x - 3) = 3 - x.
Step 2: Eliminate the square root by squaring both sides of the equation. This gives: (√(2x - 3))² = (3 - x)². Simplify to get: 2x - 3 = (3 - x)(3 - x).
Step 3: Expand the right-hand side of the equation. Use the distributive property to expand (3 - x)(3 - x), which results in: 2x - 3 = 9 - 6x + x².
Step 4: Rearrange the equation into standard quadratic form. Combine all terms on one side of the equation to get: x² - 8x + 12 = 0.
Step 5: Solve the quadratic equation using factoring, the quadratic formula, or completing the square. After finding the solutions, substitute them back into the original equation to check for extraneous solutions introduced by squaring.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
5m도움이 되었나요?
주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Radical Equations
Radical equations are equations that involve a variable within a radical (square root, cube root, etc.). To solve these equations, one typically isolates the radical on one side and then squares both sides to eliminate the radical. This process may introduce extraneous solutions, so it's essential to check all potential solutions in the original equation.
추천 영상:
Expanding Radicals
Isolating the Variable
Isolating the variable is a fundamental algebraic technique used to solve equations. This involves rearranging the equation to get the variable on one side and all other terms on the opposite side. In the context of radical equations, isolating the radical before squaring both sides is crucial for correctly solving the equation.
추천 영상:
Equations with Two Variables
Extraneous Solutions
Extraneous solutions are solutions that emerge from the process of solving an equation but do not satisfy the original equation. This is particularly common in radical equations, where squaring both sides can introduce solutions that are not valid. Therefore, it is important to substitute any found solutions back into the original equation to verify their validity.
추천 영상:
Categorizing Linear Equations
관련 실천
교과서 질문
992
views
교과서 질문
In Exercises 59–94, solve each absolute value inequality. 5 > |4 - x|
753
views
교과서 질문
Solve each equation in Exercises 83–108 by the method of your choice.
880
views
교과서 질문
The equations in Exercises 79–90 combine the types of equations we have discussed in this section. Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. 4x/(x + 3) - 12/(x - 3) = (4x2 + 36)/(x2 - 9)
920
views
교과서 질문
In Exercises 85–90, find the x-intercepts of the graph of each equation. Then use the x-intercepts to match the equation with its graph. [The graphs are labeled (a) through (f).]
<Image>
601
views
교과서 질문
In Exercises 59–94, solve each absolute value inequality. 1 < |2 - 3x|
632
views
