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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 57

Find the length and width of a rectangle whose perimeter is 36 feet and whose area is 77 square feet.

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1
Let the length of the rectangle be \(L\) feet and the width be \(W\) feet.
Write the equation for the perimeter of the rectangle: \(2L + 2W = 36\).
Simplify the perimeter equation by dividing both sides by 2: \(L + W = 18\).
Write the equation for the area of the rectangle: \(L \times W = 77\).
Use the perimeter equation to express \(L\) in terms of \(W\): \(L = 18 - W\), then substitute this into the area equation to get \((18 - W) \times W = 77\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Perimeter of a Rectangle

The perimeter of a rectangle is the total distance around it, calculated by adding twice the length and twice the width (P = 2L + 2W). Understanding this formula allows you to set up an equation relating length and width when the perimeter is known.

Area of a Rectangle

The area of a rectangle is the amount of space inside it, found by multiplying the length by the width (A = L × W). This formula helps create a second equation when the area is given, which is essential for solving for both dimensions.
추천 영상:
6:19
Systems of Inequalities

Solving Systems of Equations

When two equations involve two variables, such as length and width, solving the system means finding values that satisfy both simultaneously. Techniques include substitution or elimination, which are used here to find the rectangle’s dimensions from the perimeter and area equations.
추천 영상:
5:48
Solving Systems of Equations - Substitution