Exercises 57–59 will help you prepare for the material covered in the next section. Subtract:
Ch. 5 - Systems of Equations and Inequalities

6장, 문제 58
Find the length and width of a rectangle whose perimeter is 40 feet and whose area is 96 square feet.
검증된 단계별 안내1
Let the length of the rectangle be \(L\) feet and the width be \(W\) feet. We are given two conditions: the perimeter and the area.
Write the equation for the perimeter of a rectangle: \(2L + 2W = 40\). Simplify this to \(L + W = 20\).
Write the equation for the area of a rectangle: \(L \times W = 96\).
From the perimeter equation, express one variable in terms of the other, for example, \(L = 20 - W\).
Substitute \(L = 20 - W\) into the area equation to get \((20 - W) \times W = 96\). This will give a quadratic equation in terms of \(W\) that you can solve.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Perimeter of a Rectangle
The perimeter of a rectangle is the total distance around it, calculated as P = 2(length + width). This formula helps relate the length and width when the perimeter is known, providing one equation to solve for the dimensions.
Area of a Rectangle
The area of a rectangle is the amount of space inside it, found by multiplying length by width (A = length × width). Knowing the area gives a second equation that, combined with the perimeter, allows solving for both dimensions.
추천 영상:
Systems of Inequalities
Solving Systems of Equations
To find the length and width, you set up two equations from the perimeter and area formulas and solve them simultaneously. Techniques include substitution or elimination, which help find the values of length and width that satisfy both conditions.
추천 영상:
Solving Systems of Equations - Substitution
관련 실천
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