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Ch.7 - Periodic Properties of the Elements
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Brown 14th EditionCh.7 - Periodic Properties of the Elements문제 63d
7장, 문제 63d

Chlorine reacts with oxygen to form Cl2O7 . (d) If the oxygen in Cl2O7 is considered to have the -2 oxidation state, what is the oxidation state of the Cl? What is the electron configuration of Cl in this oxidation state?

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1
Identify the oxidation state of oxygen in Cl2O7, which is given as -2.
Let the oxidation state of chlorine be x. Since there are two chlorine atoms, the total contribution from chlorine is 2x.
Set up the equation based on the sum of oxidation states in a neutral compound: 2x + 7(-2) = 0.
Solve the equation for x to find the oxidation state of chlorine.
Determine the electron configuration of chlorine in this oxidation state by considering the loss of electrons from its ground state configuration, [Ne] 3s^2 3p^5.

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주요 개념

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Oxidation States

Oxidation states indicate the degree of oxidation of an atom in a compound. They are assigned based on a set of rules, such as the oxidation state of oxygen is typically -2 in compounds. In Cl2O7, if oxygen is -2, the total contribution from the seven oxygen atoms is -14, which helps determine the oxidation state of chlorine.
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가이드 코스
02:42
Oxidation Numbers

Balancing Oxidation States

To find the oxidation state of chlorine in Cl2O7, the sum of the oxidation states must equal the overall charge of the molecule, which is neutral (0). Given that there are two chlorine atoms, we can set up the equation: 2x + (-14) = 0, where x is the oxidation state of Cl. Solving this gives the oxidation state of Cl as +7.
추천 영상:
가이드 코스
00:58
Oxide Reactions

Electron Configuration

The electron configuration of an element describes the distribution of its electrons among the various orbitals. For chlorine in the +7 oxidation state, it loses seven electrons from its neutral state (1s² 2s² 2p⁶ 3s² 3p⁵), resulting in a configuration of 1s² 2s² 2p⁶ 3s² 3p³, indicating that it has a stable noble gas configuration with a filled outer shell.
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가이드 코스
01:33
Electron Configuration Example
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교과서 질문

Chlorine reacts with oxygen to form Cl2O7. (b) Write a balanced equation for the formation of Cl2O71l2 from the elements.

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교과서 질문

Chlorine reacts with oxygen to form Cl2O7. (c) Would you expect Cl2O7 to be more reactive toward H+1aq2 or OH-1aq2?

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교과서 질문

An element X reacts with oxygen to form XO2 and with chlorine to form XCl4. XO2 is a white solid that melts at high temperatures (above 1000 °C). Under usual conditions, XCl4 is a colorless liquid with a boiling point of 58 °C. (a) XCl4 reacts with water to form XO2 and another product. What is the likely identity of the other product?

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교과서 질문

An element X reacts with oxygen to form XO2 and with chlorine to form XCl4. XO2 is a white solid that melts at high temperatures (above 1000 °C). Under usual conditions, XCl4 is a colorless liquid with a boiling point of 58 °C. (c) By using a sourcebook such as the CRC Handbook of Chemistry and Physics, try to determine the identity of element X.

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교과서 질문

Chlorine reacts with oxygen to form Cl2O7. (a) What is the name of this product (see Table 2.6)?

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교과서 질문

An element X reacts with oxygen to form XO2 and with chlorine to form XCl4. XO2 is a white solid that melts at high temperatures (above 1000 °C). Under usual conditions, XCl4 is a colorless liquid with a boiling point of 58 °C. (b) Do you think that element X is a metal, nonmetal, or metalloid?

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