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Ch.14 - Chemical Kinetics
Tro - Chemistry: A Molecular Approach 4th Edition
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831당신이 사용하는 게 아니라요?교과서 변경
14장, 문제 69

What is the value of the rate constant at 425 K for a reaction with rate constants of 0.0117/s at 400.0 K and 0.689/s at 450.0 K?

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1
Identify that the problem involves calculating the rate constant at a specific temperature using the Arrhenius equation.
Recall the Arrhenius equation: \( k = A e^{-\frac{E_a}{RT}} \), where \( k \) is the rate constant, \( A \) is the pre-exponential factor, \( E_a \) is the activation energy, \( R \) is the gas constant, and \( T \) is the temperature in Kelvin.
Use the two given rate constants and temperatures to set up two equations based on the Arrhenius equation: \( \ln(k_1) = \ln(A) - \frac{E_a}{R} \cdot \frac{1}{T_1} \) and \( \ln(k_2) = \ln(A) - \frac{E_a}{R} \cdot \frac{1}{T_2} \).
Subtract the first equation from the second to eliminate \( \ln(A) \) and solve for \( E_a \): \( \ln(k_2) - \ln(k_1) = -\frac{E_a}{R} \left( \frac{1}{T_2} - \frac{1}{T_1} \right) \).
Once \( E_a \) is found, use it in the Arrhenius equation to solve for the rate constant \( k \) at 425 K: \( \ln(k) = \ln(A) - \frac{E_a}{R} \cdot \frac{1}{425} \).

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Arrhenius Equation

The Arrhenius equation describes how the rate constant of a reaction depends on temperature. It is expressed as k = A * e^(-Ea/RT), where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the universal gas constant, and T is the temperature in Kelvin. This relationship indicates that as temperature increases, the rate constant typically increases due to higher molecular energy and more frequent effective collisions.
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가이드 코스
01:20
Arrhenius Equation

Temperature Dependence of Rate Constants

Rate constants are temperature-dependent, meaning they change with variations in temperature. This dependence can be analyzed using the Arrhenius equation or by comparing rate constants at different temperatures. In this question, the rate constants at 400 K and 450 K are used to estimate the rate constant at an intermediate temperature of 425 K, highlighting the importance of understanding how temperature influences reaction kinetics.
추천 영상:
가이드 코스
01:24
Kw Temperature Dependence

Linear Interpolation

Linear interpolation is a mathematical method used to estimate unknown values that fall within the range of known data points. In this context, it can be applied to find the rate constant at 425 K by using the known rate constants at 400 K and 450 K. This technique assumes a linear relationship between the two known points, allowing for a straightforward calculation of the desired value.
추천 영상:
가이드 코스
01:37
Linear Form of Arrhenius Equation