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Ch. 14 - Translation and Proteins
Klug - Concepts of Genetics 12th Edition
Klug12th EditionConcepts of GeneticsISBN: 9780135564776당신이 사용하는 게 아니라요?교과서 변경
14장, 문제 33

How would the results vary in cross (a) of Problem 32 if genes A and B were linked with no crossing over between them? How would the results of cross (a) vary if genes A and B were linked and 20 map units (mu) apart?

검증된 단계별 안내
1
First, identify the original cross (a) from Problem 32 and determine the expected genotypic and phenotypic ratios assuming independent assortment (i.e., genes A and B are unlinked). This will serve as the baseline for comparison.
Next, consider the scenario where genes A and B are completely linked with no crossing over. In this case, the alleles on the same chromosome are inherited together as a single unit. Therefore, only parental gametes are produced, and recombinant gametes are absent. This will alter the expected offspring ratios compared to independent assortment.
Then, analyze the case where genes A and B are linked but 20 map units apart. Since 1 map unit corresponds to a 1% recombination frequency, a distance of 20 map units means there is a 20% chance of crossing over between the genes. Calculate the expected frequencies of parental and recombinant gametes using the recombination frequency: parental gametes will be produced at 80% combined frequency, and recombinant gametes at 20% combined frequency.
Use these gamete frequencies to determine the expected genotypic and phenotypic ratios in the offspring for the 20 map unit scenario. This will show intermediate results between complete linkage (no recombination) and independent assortment (50% recombination).
Finally, compare all three scenarios—independent assortment, complete linkage, and linkage with 20 map units—to understand how linkage and recombination frequency affect the genetic outcomes of the cross.

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주요 개념

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Genetic Linkage

Genetic linkage occurs when two genes are located close together on the same chromosome and tend to be inherited together. This reduces the likelihood of independent assortment, causing parental allele combinations to appear more frequently than recombinant types in offspring.
추천 영상:
가이드 코스
07:33
Chi Square and Linkage

Crossing Over and Recombination Frequency

Crossing over is the exchange of genetic material between homologous chromosomes during meiosis, producing recombinant gametes. The recombination frequency, expressed in map units (mu), reflects the distance between genes; 1 mu corresponds to a 1% chance of crossover between two genes.
추천 영상:
가이드 코스
11:42
Morgan's Studies of Crossing Over

Effect of Linkage Distance on Genetic Cross Outcomes

When genes are completely linked with no crossing over, only parental gametes are produced, resulting in no recombinant offspring. If genes are linked but separated by 20 map units, crossing over occurs at a 20% frequency, producing both parental and recombinant offspring in predictable ratios.
추천 영상:
가이드 코스
03:38
Maternal Effect
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교과서 질문

Deep in a previously unexplored South American rain forest, a plant species was discovered with true-breeding varieties whose flowers were pink, rose, orange, or purple. A very astute plant geneticist made a single cross, carried to the F₂ generation, as shown:

P₁: purple × pink

F₁: all purple

F₂: 27/64 purple 16/64 pink 12/64 rose 9/64 orange

Based solely on these data, he proposed both a mode of inheritance for flower pigmentation and a biochemical pathway for the synthesis of these pigments. Carefully study the data. Create a hypothesis of your own to explain the mode of inheritance. Then propose a biochemical pathway consistent with your hypothesis. How could you test the hypothesis by making other crosses?

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교과서 질문

The flow of genetic information from DNA to protein is mediated by messenger RNA. If you introduce short DNA strands (called antisense oligonucleotides) that are complementary to mRNAs, hydrogen bonding may occur and 'label' the DNA/RNA hybrid for ribonuclease-H degradation of the RNA. One study [Lloyd et al. (2001). Nucl. Acids Res. 29:3664–3673] compared the effect of different-length antisense oligonucleotides upon ribonuclease-H–mediated degradation of tumor necrosis factor (TNFα) mRNA. TNFα exhibits antitumor and pro-inflammatory activities. The following graph indicates the efficacy of various-sized antisense oligonucleotides in causing ribonuclease-H cleavage. Describe how antisense oligonucleotides interrupt the flow of genetic information in a cell.

1212
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교과서 질문

Three independently assorting genes (A, B, and C) are known to control the following biochemical pathway that provides the basis for flower color in a hypothetical plant:

Three homozygous recessive mutations are also known, each of which interrupts a different one of these steps. Determine the phenotypic results in the F1 and F2 generations resulting from the P1 crosses of true-breeding plants listed here:

speckled (AABBCC) × yellow (AAbbCC)

847
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교과서 질문

Many antibiotics are effective as drugs to fight off bacterial infections because they inhibit protein synthesis in bacterial cells. Using the information provided in the following table that highlights several antibiotics and their mode of action, discuss which phase of translation is inhibited: initiation, elongation, or termination. What other components of the translational machinery could be targeted to inhibit bacterial protein synthesis?

847
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교과서 질문

Three independently assorting genes (A, B, and C) are known to control the following biochemical pathway that provides the basis for flower color in a hypothetical plant:

Three homozygous recessive mutations are also known, each of which interrupts a different one of these steps. Determine the phenotypic results in the F1 and F2 generations resulting from the P1 crosses of true-breeding plants listed here:

colorless (aaBBCC) × green (AABBcc)

678
views
교과서 질문

Three independently assorting genes (A, B, and C) are known to control the following biochemical pathway that provides the basis for flower color in a hypothetical plant:

Three homozygous recessive mutations are also known, each of which interrupts a different one of these steps. Determine the phenotypic results in the F1 and F2 generations resulting from the P1 crosses of true-breeding plants listed here:

yellow (AAbbCC) × green (AABBcc)

531
views