Find the center of the hyperbola (x−4)216−(y+3)225=1\frac{\left(x-4\$$right)^2$$}{16}-\frac{\left(y+3\$$right)^2$$}{25}=1.

Hyperbolas

12. Conic Sections & Systems of Nonlinear Equations / Hyperbolas / 문제 2

문제 2

Find the center of the hyperbola $\frac{{(x - 4)}^{2}}{16} - \frac{{(y + 3)}^{2}}{25} = 1$ .

$open paren 4 comma 3 close paren$

$open paren 4 comma negative 3 close paren$

$open paren negative 3 comma 4 close paren$

$open paren negative 4 comma 3 close paren$