d4f91bd0-what-are-the-vertices-of-the-hyperbola-y-129-x-224-1

Question

What are the vertices of the hyperbola (y−1)29−(x+2)24=1\frac{\left(y-1\$$right)^2$$}{9}-\frac{\left(x+2\$$right)^2$$}{4}=1?

Accepted Answer

(−2,4)(-2, 4) and (−2,−2)(-2, -2)

Answer

(−2,3)\left(-2,3\right) and (−2,−2)(-2, -2)

Answer

(−2,4)\left(-2,4\right) and (−2,2)\left(-2,2\right)

Answer

(−2,3)\left(-2,3\right) and (−2,2)\left(-2,2\right)

What are the vertices of the hyperbola (y−1)29−(x+2)24=1\(\frac{\left(y-1\right)^2}{9}\)-\(\frac{\left(x+2\right)^2}{4}\)=1?