Describe the formation of an aqueous KI solution, when solid KI d...

Question

Describe the formation of an aqueous KI solution, when solid KI dissolves in water.

Accepted Answer

Welcome back. Everyone which of the following occurs during the dissolution of solid sodium bromide in water. Choice A states that solid sodium bromide breaks apart into sodium and bromide ions surrounded by water molecules. Choice B states that sodium bromide reacts with water to form a new compound. Choice C states that sodium sodium bromide breaks down into smaller molecules which are surrounded by water molecules. And choice D states that sodium bromide remains intact and does not dissolve in water. We're going to begin by analyzing our compound sodium bromide and A B R recognize that it consists of our metal sodium and our nonmetal bromine which means that we have an ionic compound. Let's next recall our solubility rules for bromides in which all bromides are soluble. With the exception of silver bromides, lead bromides and mercury bromides. So these would be examples of insoluble bromides. Now because we have sodium bromide, we do have a soluble bromide. So we would give it the label A Q meaning it's soluble in water. And this means that it would fully dissociate into our sodium plus one ion as well as our bromide one minus anion as products recognize that we have our dissolved ions in water where we want to visualize our molecule of water where we have two hydrogens bonded to a central oxygen with two lone pairs on itself. Let's recall that water is considered polar. And therefore, we have based on our lower electron negativity for hydrogen, a slightly positive charge on our hydrogen atoms. And based on the higher electron negativity of oxygen, a slightly negative charge on our oxygen atom, meaning we have a dipole in our direction of oxygen. And because of this, we have an attraction between our ions where our bromide ions in solution through the process of salvation would be attracted to our slightly positive hydrogens in the water molecule. And our sodium ions in solution would be attracted to through the process of salvation. Our slightly negative charge on oxygen in our water molecule and this attraction between our water molecules and our ions in solution from sodium bromide would keep our ions separate from one another. And again, this process is known as salvation slash hydration. Now, looking at our answer choices, we would rule out choice B because sodium bromide is not going to be reacting with water to form a new compound. It's going to be dissociating into its ions. Since it's a soluble bromide, we would then rule out choice d based on what we outlined. And we can also rule out choice C because we would not break our sodium bromide down into smaller molecules, we would break it down into its ions which are surrounded by water molecules. So that leaves us with choice. A which states that during the dissolution of sodium bromide in water, solid, sodium bromide breaks apart into sodium and bromide anions which are surrounded by water molecules. So a is our final answer. I hope that this made sense and let us know if you have any questions.

Describe the formation of an aqueous KI solution, when solid KI dissolves in water.

주요 개념

Dissolution Process

Ionic Compounds in Water

Aqueous Solutions

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