Physics with Calculus
ΦB=∫13(2x)4dx\(\Phi\)_{B}=\(\int\)_1^3\(\left\)(2x\(\right\))4\,\(\mathrm{dx}\)
ΦB=∫13(2x)xdx\(\Phi\)_{B}=\(\int\)_1^3\(\left\)(2x\(\right\))x\,\(\mathrm{dx}\)
ΦB=∫04(2x)4dx\(\Phi\)_{B}=\(\int\)_0^4\(\left\)(2x\(\right\))4\,\(\mathrm{dx}\)
ΦB=∫13(2x)4cos90∘dx\(\Phi\)_{B}=\(\int\)_1^3\(\left\)(2x\(\right\))4\(\cos\)90^{\(\circ\)}\,\(\mathrm{dx}\)