Physics with Calculus
ΦB=B/AΦ_B = B/A
ΦB=∫B⋅dA\(\Phi\)_{B}=\(\int\)_{}^{}B\(\cdot\) dA
ΦB=∫A⋅dB\(\Phi\)_{B}=\(\int\)_{}^{}A\(\cdot\) dB
ΦB=∫B×dA\(\Phi\)_{B}=\(\int\)_{}^{}B\(\times\) dA