which-antiderivative-is-correct

Question

Determine the antiderivative of 1x2\displaystyle\frac{1}{$$x^2$$}.

Accepted Answer

∫1x2 dx=−1x+C{\displaystyle\int\frac{1}{$$x^2$$}\,dx=-\frac{1}{x}+C}

Answer

∫1x2 dx=1x+C\displaystyle\int\frac{1}{$$x^2$$}\,dx=\frac{1}{x}+C

Answer

∫1x2 dx=−12x2+C\displaystyle\displaystyle\int\frac{1}{$$x^2$$}\,dx=-\frac{1}{$$2x^2$$}+C

Answer

∫1x2 dx=ln⁡x+C\displaystyle\int\frac{1}{$$x^2$$}\,dx=\ln x+C

Determine the antiderivative of 1x2\(\displaystyle\)\(\frac{1}{x^2}\).