A 6750-kg helicopter accelerates upward at 0.80m/s² while lifting a 1080-kg frame at a construction site, Fig. 4–66.
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(c) What force does the cable exert on the helicopter?

검증된 단계별 안내

Identify the total mass being accelerated. This includes both the mass of the helicopter and the mass of the frame. Add these two masses together.

Calculate the total force needed to accelerate this combined mass upward. Use Newton's second law, F = ma, where 'm' is the total mass and 'a' is the acceleration.

Determine the force of gravity acting on the combined mass. This force can be calculated using the formula F_gravity = mg, where 'g' is the acceleration due to gravity (approximately 9.81 m/s²).

Calculate the total force exerted by the cable. This force must not only support the weight of the helicopter and the frame against gravity but also provide the additional force required for the upward acceleration. Add the force needed for acceleration to the gravitational force.

The force exerted by the cable on the helicopter is the total force calculated in the previous step, as this force is transmitted through the cable to lift both the helicopter and the frame.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Newton's Second Law of Motion

Newton's Second Law states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). This principle is crucial for analyzing the forces acting on the helicopter and the frame, as it allows us to calculate the net force required for the upward acceleration.

Weight

Weight is the force exerted by gravity on an object, calculated as the product of its mass and the acceleration due to gravity (W = mg). In this scenario, both the helicopter and the frame have weights that must be considered when determining the total force exerted by the cable.

Tension in the Cable

Tension is the force transmitted through a cable or rope when it is pulled tight by forces acting from opposite ends. In this case, the tension in the cable must counteract the combined weight of the helicopter and the frame while also providing the additional force needed for the upward acceleration.