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Ch. 23 - Electric Potential
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179당신이 사용하는 게 아니라요?교과서 변경
22장, 문제 38

A thin rod of length 2ℓ is centered on the x axis as shown in Fig. 23–46. The rod carries a uniformly distributed charge Q. Determine the potential V as a function of y for points along the y axis. Let V = 0 at infinity.
Diagram of a charged rod on the x-axis, with labeled axes showing length 2ℓ and points along the y-axis for potential calculation.

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Start by recalling the formula for the electric potential due to a point charge: \( V = \frac{k_e q}{r} \), where \( k_e \) is Coulomb's constant, \( q \) is the charge, and \( r \) is the distance from the charge to the point of interest. For a continuous charge distribution, the potential is calculated by integrating over the charge distribution: \( V = \int \frac{k_e dq}{r} \).
Set up the coordinate system. The rod is centered on the x-axis, with its length extending from \( -\ell \) to \( \ell \). The point of interest is along the y-axis at a distance \( y \) from the origin. The distance \( r \) from a point on the rod to the point on the y-axis is given by \( r = \sqrt{x^2 + y^2} \), where \( x \) is the position along the rod.
Express the charge element \( dq \) in terms of the linear charge density \( \lambda \), where \( \lambda = \frac{Q}{2\ell} \). The charge element is then \( dq = \lambda dx \), where \( dx \) is an infinitesimal segment of the rod.
Substitute \( dq \) and \( r \) into the integral for the potential: \( V = \int_{-\ell}^{\ell} \frac{k_e \lambda dx}{\sqrt{x^2 + y^2}} \). This integral accounts for the contribution to the potential from each infinitesimal segment of the rod.
Solve the integral. Since \( \lambda \) and \( k_e \) are constants, they can be factored out of the integral: \( V = k_e \lambda \int_{-\ell}^{\ell} \frac{dx}{\sqrt{x^2 + y^2}} \). Use a standard integral formula for \( \int \frac{dx}{\sqrt{x^2 + a^2}} \), which evaluates to \( \ln(x + \sqrt{x^2 + a^2}) \). Apply the limits of integration from \( -\ell \) to \( \ell \) to find the final expression for \( V \).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Electric Potential

Electric potential (V) is the amount of electric potential energy per unit charge at a point in an electric field. It is a scalar quantity and is measured in volts (V). The potential due to a charged object can be calculated by integrating the contributions from each infinitesimal charge element, taking into account the distance from the charge to the point of interest.
추천 영상:
가이드 코스
07:33
Electric Potential

Coulomb's Law

Coulomb's Law describes the force between two point charges. It states that the force (F) between two charges is directly proportional to the product of the magnitudes of the charges (Q1 and Q2) and inversely proportional to the square of the distance (r) between them. This law is fundamental in calculating the electric field and potential due to distributed charges.
추천 영상:

Superposition Principle

The superposition principle states that the total electric potential at a point due to multiple charges is the algebraic sum of the potentials due to each charge considered separately. This principle allows for the calculation of the potential from a continuous charge distribution, such as the uniformly charged rod in the question, by integrating the contributions from each infinitesimal segment of the rod.
추천 영상:
가이드 코스
03:32
Superposition of Sinusoidal Wave Functions
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