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Ch. 34 - The Wave Nature of Light: Interference and Polarization
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179당신이 사용하는 게 아니라요?교과서 변경
33장, 문제 2

Monochromatic light falling on two slits 0.018 mm apart produces the fifth-order bright fringe at a 12° angle. What is the wavelength of the light used?

검증된 단계별 안내
1
Step 1: Recall the formula for the position of bright fringes in a double-slit interference pattern: \( d \sin \theta = m \lambda \), where \( d \) is the distance between the slits, \( \theta \) is the angle of the bright fringe, \( m \) is the order of the fringe, and \( \lambda \) is the wavelength of the light.
Step 2: Identify the given values from the problem: \( d = 0.018 \; \text{mm} = 0.018 \times 10^{-3} \; \text{m} \), \( \theta = 12^{\circ} \), and \( m = 5 \) (fifth-order bright fringe).
Step 3: Rearrange the formula to solve for the wavelength \( \lambda \): \( \lambda = \frac{d \sin \theta}{m} \).
Step 4: Substitute the known values into the formula: \( \lambda = \frac{(0.018 \times 10^{-3}) \sin(12^{\circ})}{5} \).
Step 5: Use a calculator to compute \( \sin(12^{\circ}) \), multiply by \( d \), and divide by \( m \) to find the wavelength \( \lambda \). Ensure the final result is expressed in meters or converted to nanometers (1 nm = \( 10^{-9} \; \text{m} \)).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
6m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Double-Slit Experiment

The double-slit experiment demonstrates the wave nature of light through interference patterns created when light passes through two closely spaced slits. When monochromatic light is used, it produces alternating bright and dark fringes on a screen due to constructive and destructive interference, respectively. The position of these fringes depends on the wavelength of the light and the distance between the slits.
추천 영상:
가이드 코스
12:00
Young's Double Slit Experiment

Interference Pattern

An interference pattern is formed when two or more overlapping waves combine, resulting in regions of increased (constructive interference) and decreased (destructive interference) intensity. In the context of the double-slit experiment, the bright fringes correspond to points where the path difference between the waves from the two slits is an integer multiple of the wavelength, while dark fringes occur at half-integer multiples.
추천 영상:
가이드 코스
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Wave Interference & Superposition

Wavelength Calculation

The wavelength of light can be calculated using the formula for the position of bright fringes in a double-slit setup: d sin(θ) = mλ, where d is the distance between the slits, θ is the angle of the fringe, m is the order of the fringe, and λ is the wavelength. By rearranging this equation, one can solve for the wavelength when the other variables are known, such as the slit separation and the angle of the observed fringe.
추천 영상:
가이드 코스
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Unknown Wavelength of Laser through Double Slit