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Ch 06: Dynamics I: Motion Along a Line
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 60

A particle of mass m moving along the x-axis experiences the net force Fₓ = ct, where c is a constant. The particle has velocity v₀ₓ at t = 0. Find an algebraic expression for the particle's velocity vₓ at a later time t.

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Start by recalling Newton's second law of motion, which states that the net force acting on an object is equal to the rate of change of its momentum. For a particle of constant mass m, this simplifies to: F_x = m \(\frac{dv_x}{dt}\).
Substitute the given force F_x = ct into the equation: m \(\frac{dv_x}{dt}\) = ct. Rearrange to isolate \(\frac{dv_x}{dt}\): \(\frac{dv_x}{dt}\) = \(\frac{ct}{m}\).
Integrate both sides with respect to time to find the velocity v_x. The left-hand side becomes \(\int\) dv_x, and the right-hand side becomes \(\int\) \(\frac{ct}{m}\) dt: v_x = \(\int\) \(\frac{ct}{m}\) dt.
Perform the integration on the right-hand side. Since c and m are constants, they can be factored out: v_x = \(\frac{c}{m}\) \(\int\) t dt. The integral of t is \(\frac{t^2}{2}\), so: v_x = \(\frac{c}{m}\) \(\cdot\) \(\frac{t^2}{2}\) + C, where C is the constant of integration.
Determine the constant of integration C using the initial condition. At t = 0, the velocity is v_{0x}. Substituting these values into the equation: v_{0x} = \(\frac{c}{m}\) \(\cdot\) \(\frac{(0)^2}{2}\) + C, we find C = v_{0x}. Thus, the final expression for the velocity is: v_x = \(\frac{c}{2m}\) t^2 + v_{0x}.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

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