Ch 32: AC Circuits

Knight Calc - Physics for Scientists and Engineers 5th Edition

Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796당신이 사용하는 게 아니라요?교과서 변경

Knight Calc 5th Edition

Ch 32: AC Circuits

문제 11a

32장, 문제 11a

A 20 nF capacitor is connected across an AC generator that produces a peak voltage of 5.0 V. At what frequency f is the peak current 50 mA?

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Determine the relationship between the peak current, peak voltage, and capacitive reactance using the formula:

I_{peak} = \(\frac{V_{peak}\)}{X_C}

, where

I_{peak}

is the peak current,

V_{peak}

is the peak voltage, and

X_C

is the capacitive reactance.

Express the capacitive reactance

X_C

in terms of the capacitance and frequency using the formula:

X_C = \(\frac{1}{2 \pi f C}\)

, where

f

is the frequency and

C

is the capacitance.

Substitute the expression for

X_C

into the formula for

I_{peak}

I_{peak} = V_{peak} \(\cdot\) 2 \(\pi\) f C

. Rearrange this equation to solve for the frequency

f

f = \(\frac{I_{peak}\)}{2 \(\pi\) V_{peak} C}

Substitute the given values into the formula:

I_{peak} = 50 \(\text{ mA}\) = 50 \(\times\) 10^{-3} \(\text{ A}\)

V_{peak} = 5.0 \(\text{ V}\)

, and

C = 20 \(\text{ nF}\) = 20 \(\times\) 10^{-9} \(\text{ F}\)

Simplify the expression to calculate the frequency

f

. Ensure that all units are consistent (e.g., convert nanofarads to farads and milliamps to amps) before performing the calculation.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Capacitance

Capacitance is the ability of a capacitor to store electrical charge per unit voltage. It is measured in farads (F), and in this case, the capacitor has a capacitance of 20 nF (nanofarads). The relationship between charge (Q), voltage (V), and capacitance (C) is given by the formula Q = C * V.

AC Circuit and Impedance

In an AC circuit, the impedance (Z) is the total opposition to current flow, which includes resistance and reactance. For a capacitor, the reactance (Xc) is frequency-dependent and is calculated using the formula Xc = 1 / (2πfC). Understanding impedance is crucial for analyzing how capacitors behave in AC circuits.

Ohm's Law in AC Circuits

Ohm's Law applies to AC circuits as well, where the peak current (I) can be related to the peak voltage (V) and impedance (Z) by the formula I = V / Z. In this scenario, knowing the peak current and voltage allows us to determine the frequency at which the circuit operates, linking the concepts of capacitance and impedance.