Skip to main content
Ch 13: Gravitation
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
13장, 문제 34a

A thin, uniform rod has length L and mass M. A small uniform sphere of mass m is placed a distance x from one end of the rod, along the axis of the rod (Fig. E13.34). Calculate the gravitational potential energy of the rod–sphere system. Take the potential energy to be zero when the rod and sphere are infinitely far apart. Show that your answer reduces to the expected result when x is much larger than L.

검증된 단계별 안내
1
Understand that the gravitational potential energy (U) between two masses is given by the formula: U = -GMmr, where G is the gravitational constant, M and m are the masses, and r is the distance between the centers of the two masses.
Consider the rod as a collection of infinitesimally small mass elements, each contributing to the gravitational potential energy with the sphere. Let the linear mass density of the rod be λ = ML.
Set up an integral to calculate the total gravitational potential energy between the rod and the sphere. Consider a small element of the rod of length dx at a distance x from the sphere. The mass of this element is dm = λdx.
The potential energy contribution from this small element is dU = -Gmdmr, where r is the distance from the sphere to the element. Integrate this expression from x to x + L to find the total potential energy.
To show that the result reduces to the expected form when x is much larger than L, consider the approximation where the rod can be treated as a point mass located at its center of mass. The distance from the sphere to the center of mass of the rod is approximately x + L/2, and use this in the potential energy formula to verify the expected result.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
9m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Gravitational Potential Energy

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. For two masses, it is given by the formula U = -G(Mm)/r, where G is the gravitational constant, M and m are the masses, and r is the distance between their centers. This concept is crucial for calculating the energy of the rod-sphere system as it depends on their separation.
추천 영상:
가이드 코스
06:35
Gravitational Potential Energy

Integration in Continuous Mass Distributions

When dealing with objects like rods, which have continuous mass distributions, integration is used to calculate quantities like gravitational potential energy. The rod can be divided into infinitesimally small elements, each contributing to the total potential energy. This requires setting up an integral over the length of the rod, considering the distance from each element to the sphere.
추천 영상:
가이드 코스
10:06
Using Calculus to Solve Mass Distribution Problems

Limit Analysis

Limit analysis involves examining the behavior of a function as a variable approaches a particular value, often infinity. In this problem, analyzing the limit as x becomes much larger than L helps verify the solution by showing it simplifies to a known result. This concept ensures the solution is consistent with physical intuition and known cases, such as treating the rod as a point mass when far away.
추천 영상:
가이드 코스
05:00
Dimensional Analysis
관련 실천
교과서 질문

A uniform, spherical, 1000.0 kg1000.0\(\text{ kg}\) shell has a radius of 5.00 m5.00\(\text{ m}\). Sketch a qualitative graph of the magnitude of the gravitational force this sphere exerts on a point mass m as a function of the distance rr of mm from the center of the sphere. Include the region from r=0r = 0 to rr\(\to\]\infty\).

1751
views
교과서 질문

Consider the ringshaped body of Fig. E13.35. A particle with mass m is placed a distance x from the center of the ring, along the line through the center of the ring and perpendicular to its plane. (a) Calculate the gravitational potential energy U of this system. Take the potential energy to be zero when the two objects are far apart. (b) Show that your answer to part (a) reduces to the expected result when x is much larger than the radius a of the ring. (c) Use Fx = -dU/dx to find the magnitude and direction of the force on the particle (see Section 7.4). (d) Show that your answer to part (c) reduces to the expected result when x is much larger than a. (e) What are the values of U and Fx when x = 0? Explain why these results make sense.

744
views
교과서 질문

You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 395.0 N in the rope. If Sneezy hangs from a similar rope while delivering presents at the earth's equator, what will the tension in it be? (Recall that the earth is rotating about an axis through its north and south poles.)

2770
views
1
comments
교과서 질문

A thin, uniform rod has length L and mass M. A small uniform sphere of mass m is placed a distance x from one end of the rod, along the axis of the rod (Fig. E13.34). Use Fx = -dU/dx to find the magnitude and direction of the gravitational force exerted on the sphere by the rod (see Section 7.4). Show that your answer reduces to the expected result when x is much larger than L.

2352
views
1
rank
교과서 질문

A uniform, solid, 1000.0-kg sphere has a radius of 5.00 m. Find the gravitational force this sphere exerts on a 2.00-kg point mass placed at the following distances from the center of the sphere: (i) 5.01 m, (ii) 2.50 m.

1256
views
교과서 질문

A uniform, spherical, 1000.0-kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 2.00-kg point mass placed at the following distances from the center of the shell: (i) 5.01 m, (ii) 4.99 m, (iii) 2.72 m.

1767
views