How much work would it take to push two protons very slowly from a separation of 2.00×10−102.00\$$times10^{-10} m (a $$typical atomic distance) to 3.00×10−153.00\$$times10^{-15} m (a $$typical nuclear distance)? If the protons are both released from rest at the closer distance in part (a), how fast are they moving when they reach their original separation?

Ch 23: Electric Potential

Young & Freedman Calc - University Physics 14th Edition

Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경

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Young & Freedman Calc 14th Edition

Ch 23: Electric Potential

문제 4

23장, 문제 4

How much work would it take to push two protons very slowly from a separation of $2.00 \times 10^{- 10}$ m (a typical atomic distance) to $3.00 \times 10^{- 15}$ m (a typical nuclear distance)? If the protons are both released from rest at the closer distance in part (a), how fast are they moving when they reach their original separation?

검증된 단계별 안내

Step 1: Understand the concept of electric potential energy. The work done in moving charges is related to the change in electric potential energy. For two point charges, the electric potential energy U is given by the formula:

- \frac{k q_{1} q_{2}}{r}

, where k is Coulomb's constant, q1 and q2 are the charges, and r is the separation distance.

Step 2: Calculate the initial and final electric potential energy. Use the formula for electric potential energy to find the initial energy at 2.00x10^-10 m and the final energy at 3.00x10^-15 m. Remember that the charge of a proton is approximately 1.60x10^-19 C.

Step 3: Determine the work done. The work done in moving the protons is equal to the change in electric potential energy, which is the final potential energy minus the initial potential energy. Use the values calculated in Step 2 to find this difference.

Step 4: For part (b), apply the conservation of energy principle. When the protons are released from rest, their initial kinetic energy is zero, and their potential energy is at the closer distance. As they move apart, their potential energy decreases, and their kinetic energy increases.

Step 5: Calculate the final speed of the protons. Use the conservation of energy equation:

K_{f} = U_{i} - U_{f}

, where Kf is the final kinetic energy, Ui is the initial potential energy, and Uf is the final potential energy. Solve for the final speed using the relation between kinetic energy and speed:

K_{f} = \frac{1}{2} m v^{2}

, where m is the mass of a proton.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Electrostatic Force

Electrostatic force is the force between charged particles, described by Coulomb's law. It states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Understanding this force is crucial for calculating the work needed to move charged particles like protons.

Work-Energy Principle

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. In this context, calculating the work done to move protons involves understanding how energy is transferred and transformed, particularly from potential to kinetic energy as the protons move.

Conservation of Energy

Conservation of energy is a fundamental principle stating that energy cannot be created or destroyed, only transformed. When protons are released, their potential energy due to electrostatic forces is converted into kinetic energy, allowing us to calculate their speed at different separations using energy conservation.

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교과서 질문

Two protons, starting several meters apart, are aimed directly at each other with speeds of $2.00 \times 10^{5}$ m/s, measured relative to the earth. Find the maximum electric force that these protons will exert on each other.

Two protons are released from rest when they are $0.750$ nm apart. What is the maximum acceleration they will achieve and when does this acceleration occur?

A small metal sphere, carrying a net charge of $q_{1} = - 2.80$ μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of $q_{2} = - 7.80$ μC and mass $1.50$ g, is projected toward $q sub 1$ . When the two spheres are $0.800$ m apart, $q sub 2$ , is moving toward $q sub 1$ with speed $22.0$ m/s (Fig. E $23.5$ ). Assume that the two spheres can be treated as point charges. You can ignore the force of gravity. What is the speed of $q sub 2$ when the spheres are $0.400$ m apart?

A point charge $q sub 1 equals positive 2.40$ $μ$ C is held stationary at the origin. A second point charge $q_{2} = - 4.30$ $μ$ C moves from the point $x equals 0.150$ m, $y equals 0$ to the point $x equals 0.250$ m, $y equals 0.250$ m. How much work is done by the electric force on $q sub 2$ ?

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