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Ch 21: Electric Charge and Electric Field
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Young & Freedman Calc 14th EditionCh 21: Electric Charge and Electric Field문제 34b
21장, 문제 34b

A +8.75+8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a −6.50-6.50-mC point charge by a light, nonconducting 2.502.50-cm wire. A uniform electric field of magnitude 1.85×1081.85\(\times\)10^8 N/CN/C is directed parallel to the wire, as shown in Fig. E21.3421.34. What would the tension be if both charges were negative?
Two point charges, -6.50 μC and 8.75 μC, connected by a 2.50 cm wire, with an electric field pointing right.

검증된 단계별 안내
1
First, understand that the tension in the wire is due to the forces acting on the charges. These forces include the electric force due to the electric field and the electrostatic force between the charges.
Calculate the force on each charge due to the electric field using the formula: \( F = qE \), where \( q \) is the charge and \( E \) is the electric field. Since both charges are negative, the direction of the force will be opposite to the direction of the electric field.
Calculate the electrostatic force between the two charges using Coulomb's law: \( F = \frac{k |q_1 q_2|}{r^2} \), where \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between them. Since both charges are negative, the force will be attractive.
Determine the net force on each charge by considering the direction of the forces. The tension in the wire will be equal to the net force acting on either charge, as the system is in equilibrium.
Finally, express the tension in terms of the calculated forces. The tension will be the sum of the magnitudes of the electric force and the electrostatic force, considering their directions.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
8m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Coulomb's Law

Coulomb's Law describes the electrostatic interaction between electrically charged particles. The force between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. This force is attractive if the charges are of opposite signs and repulsive if they are of the same sign.
추천 영상:
09:52
Coulomb's Law

Electric Field

An electric field is a vector field around a charged particle that represents the force exerted on other charges in the vicinity. The strength and direction of the electric field are defined by the force per unit charge experienced by a positive test charge placed in the field. In this problem, the uniform electric field affects the forces on the charges, influencing the tension in the wire.
추천 영상:
03:16
Intro to Electric Fields

Tension in a Wire

Tension in a wire is the force exerted along the wire, which arises due to the forces acting on the objects connected by the wire. In this scenario, the tension results from the balance of electrostatic forces between the charges and the force due to the external electric field. The tension will change if the charges are both negative, as the direction and magnitude of forces will differ.
추천 영상:
09:57
Magnetic Force on Current-Carrying Wire
관련 실천
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교과서 질문

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교과서 질문

A +8.75+8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a −6.50-6.50-mC point charge by a light, nonconducting 2.502.50-cm wire. A uniform electric field of magnitude 1.85×1081.85\(\times\)10^8 N/CN/C is directed parallel to the wire, as shown in Fig. E21.3421.34. Find the tension in the wire.

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