Skip to main content
Ch 44: Particle Physics and Cosmology
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610당신이 사용하는 게 아니라요?교과서 변경
44장, 문제 32

In an experiment done in a laboratory on the earth, the wavelength of light emitted by a hydrogen atom in the n=4n = 4 to n=2n = 2 transition is 486.1486.1 nm. In the light emitted by the quasar 3C273 (see Problem 36.6036.60), this spectral line is redshifted to 563.9563.9 nm. Assume the redshift is described by Eq. (44.1444.14) and use the Hubble law to calculate the distance in light-years of this quasar from the earth.

검증된 단계별 안내
1
Step 1: Understand the redshift phenomenon. Redshift occurs when the wavelength of light emitted by an object is stretched due to the object moving away from the observer. The redshift (z) is defined as \( z = \frac{\lambda_{observed} - \lambda_{emitted}}{\lambda_{emitted}} \), where \( \lambda_{observed} \) is the observed wavelength and \( \lambda_{emitted} \) is the emitted wavelength.
Step 2: Calculate the redshift \( z \) using the given wavelengths. Substitute \( \lambda_{observed} = 563.9 \, \text{nm} \) and \( \lambda_{emitted} = 486.1 \, \text{nm} \) into the formula \( z = \frac{\lambda_{observed} - \lambda_{emitted}}{\lambda_{emitted}} \).
Step 3: Use the Hubble law to relate the redshift to the distance of the quasar. The Hubble law states \( v = H_0 \cdot d \), where \( v \) is the recession velocity, \( H_0 \) is the Hubble constant, and \( d \) is the distance. The recession velocity \( v \) can be approximated as \( v \approx c \cdot z \), where \( c \) is the speed of light.
Step 4: Substitute \( v = c \cdot z \) into the Hubble law to find the distance \( d \). Rearrange the equation to \( d = \frac{v}{H_0} \), and substitute \( v \approx c \cdot z \) to get \( d = \frac{c \cdot z}{H_0} \). Use the known values for \( c \) (speed of light) and \( H_0 \) (Hubble constant, typically \( 70 \, \text{km/s/Mpc} \) or another given value).
Step 5: Convert the distance \( d \) from megaparsecs (Mpc) to light-years. Use the conversion factor \( 1 \, \text{Mpc} = 3.26 \times 10^6 \, \text{light-years} \). Multiply the distance in Mpc by this factor to express the final distance in light-years.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Wavelength and Energy Levels

In atomic physics, the wavelength of light emitted during electron transitions between energy levels is crucial. For hydrogen, when an electron moves from a higher energy level (n=4) to a lower one (n=2), it emits a photon with a specific wavelength, which can be calculated using the Rydberg formula. This relationship between energy levels and emitted wavelengths is foundational for understanding atomic spectra.
추천 영상:
05:42
Unknown Wavelength of Laser through Double Slit

Redshift

Redshift occurs when light from an object is stretched to longer wavelengths as it moves away from an observer, often due to the expansion of the universe. It is quantified by the formula z = (λ_observed - λ_emitted) / λ_emitted, where λ represents the wavelengths. In cosmology, redshift is a key indicator of the velocity and distance of celestial objects, such as quasars.

Hubble's Law

Hubble's Law states that the recessional velocity of a galaxy (v) is directly proportional to its distance (d) from Earth, expressed as v = H₀ * d, where H₀ is the Hubble constant. This relationship allows astronomers to estimate distances to faraway galaxies and quasars based on their redshift, providing insights into the structure and expansion of the universe.
추천 영상:
10:20
Gauss' Law