Find the degree measure of θ if it exists. Do not use a calculator.
θ = sin⁻¹ 2

검증된 단계별 안내

Recall the definition of the inverse sine function, $\sin^{-1} x$, which gives the angle $\theta$ such that $\sin \theta = x$ and $\theta$ lies within the range $[-90^\circ, 90^\circ]$ (or $[-\frac{\pi}{2}, \frac{\pi}{2}]$$).

Understand the domain of the sine function: since $\sin \theta$ can only take values between $-1$ and $1$ for real angles $\theta$, the input to $\sin^{-1}$ must be within this range.

Check the given value inside the inverse sine: here, it is $2$, which is outside the domain $[-1, 1]$.

Since $2$ is not in the domain of the inverse sine function, there is no real angle $\theta$ such that $\sin \theta = 2$.

Therefore, conclude that $\theta = \sin^{-1} 2$ does not exist as a real number (no degree measure satisfies this).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Domain of the Sine Function

The sine function outputs values only between -1 and 1 for real angles. Any input outside this range, such as 2, is not possible for sine, meaning sin⁻¹(2) does not correspond to a real angle.

Inverse Sine Function (Arcsin)

The inverse sine function, sin⁻¹(x), returns the angle whose sine is x, but only if x is within the domain [-1, 1]. It is used to find angles from sine values, but it is undefined for values outside this range.

Understanding Restrictions in Trigonometric Functions

Trigonometric functions have specific domains and ranges that limit their outputs and inputs. Recognizing these restrictions helps determine whether an expression like sin⁻¹(2) has a valid solution or not.

Find the degree measure of θ if it exists. Do not use a calculator.θ = sin⁻¹ 2