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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 53

Solve each equation for all exact solutions, in degrees.
tan θ - sec θ = 1

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Start with the given equation: \(\tan \theta - \sec \theta = 1\).
Recall the definitions of tangent and secant in terms of sine and cosine: \(\tan \theta = \frac{\sin \theta}{\cos \theta}\) and \(\sec \theta = \frac{1}{\cos \theta}\).
Rewrite the equation using these definitions: \(\frac{\sin \theta}{\cos \theta} - \frac{1}{\cos \theta} = 1\).
Combine the terms on the left side over the common denominator \(\cos \theta\): \(\frac{\sin \theta - 1}{\cos \theta} = 1\).
Multiply both sides by \(\cos \theta\) (noting \(\cos \theta \neq 0\)) to get \(\sin \theta - 1 = \cos \theta\), then rearrange to \(\sin \theta - \cos \theta = 1\) and proceed to solve for \(\theta\).

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