ngle-with-the-outward-area-vector-which-expression-correctly-represents-the-flux

Question

A vertical rectangular surface has height HH and spans x=0x = 0 to x=ax = a. A magnetic field B(x)B(x) points horizontally through the surface, making a constant angle θ	heta with the outward area vector. Which expression correctly represents the flux?

Accepted Answer

ΦB=∫0aB(x)Hcos⁡θ dx\Phi_{B}=\$$int_0$$^{a}B\left(xight)H\cos	heta\,\mathrm{dx}

Answer

ΦB=∫0HB(x)acos⁡θ dx\Phi_{B}=\$$int_0$$^{H}B\left(xight)a\cos	heta\,\mathrm{dx}

Answer

ΦB=∫0aB(x)Hsin⁡θ dx\Phi_{B}=\$$int_0$$^{a}B\left(xight)H\sin	heta\,\mathrm{dx}

Answer

ΦB=B(a)HacosθΦ_B = B(a)Ha cosθ

A vertical rectangular surface has height HH and spans x=0x = 0 to x=ax = a. A magnetic field B(x)B(x) points horizontally through the surface, making a constant angle θ\(\theta\) with the outward area vector. Which expression correctly represents the flux?

A vertical rectangular surface has height $H$ and spans $x equals 0$ to $x = a$ . A magnetic field $B (x)$ points horizontally through the surface, making a constant angle $θ$ with the outward area vector. Which expression correctly represents the flux?