-4-s-the-force-follows-ft-6-t-22-n-what-total-impulse-is-delivered-from-0-to-4-s

Question

A force-time graph has two parts: from 00  to 22  s, force increases linearly from 00  N to 66  N; from 22  to 44  s, the force follows F(t)=6+(t−2)2F(t) = 6 + (t - $$2)^2  N. $$What total impulse is delivered from 00  to 44  s?

Accepted Answer

623 N⋅s\displaystyle\frac{62}{3}	ext{ N}\cdot	ext{s}

Answer

20 N⋅s20	ext{ N}\cdot	ext{s}

Answer

503 N⋅s\displaystyle\frac{50}{3}	ext{ N}\cdot	ext{s}

Answer

26 N⋅s26	ext{ N}\cdot	ext{s}

A force-time graph has two parts: from 00 to 22 s, force increases linearly from 00 N to 66 N; from 22 to 44 s, the force follows F(t)=6+(t−2)2F(t) = 6 + (t - 2)^2 N. What total impulse is delivered from 00 to 44 s?

A force-time graph has two parts: from $0$ to $2$ s, force increases linearly from $0$ N to $6$ N; from $2$ to $4$ s, the force follows $F (t) = 6 + (t - 2)^{2}$ N. What total impulse is delivered from $0$ to $4$ s?