or-form-of-coulombs-law-after-substituting-rhat-rvector-r-into-f-k-q1-q2-r2-rhat

Question

Which expression is the correct vector form of Coulomb's law after substituting R^=R→R\hat{R}=\frac{\overrightarrow{R}}{R} into F→=kq1q2R2⋅R^\overrightarrow{F}=\frac{kq1q2}{$$R^2$$}\cdot\hat{R}?

Accepted Answer

F→=k⋅q1⋅q2R3⋅R→\overrightarrow{F}=\frac{k\cdot q1\cdot q2}{$$R^3$$}\cdot\overrightarrow{R}

Answer

F→=k⋅q1⋅q2R4⋅R→\overrightarrow{F}=\frac{k\cdot q1\cdot q2}{$$R^4$$}\cdot\overrightarrow{R}

Answer

F→=k⋅q1⋅q2R2⋅R→\overrightarrow{F}=\frac{k\cdot q1\cdot q2}{$$R^2$$}\cdot\overrightarrow{R}

Answer

F→=k⋅q1⋅q2R⋅R^\overrightarrow{F}=\frac{k\cdot q1\cdot q2}{R^{}}\cdot\hat{R}

Which expression is the correct vector form of Coulomb's law after substituting R^=R→R\(\hat{R}\)=\(\frac{\overrightarrow{R}\)}{R} into F→=kq1q2R2⋅R^\(\overrightarrow{F}\)=\(\frac{kq1q2}{R^2}\[\cdot\]\hat{R}\)?

Which expression is the correct vector form of Coulomb's law after substituting $\hat{R} = \frac{\vec{R}}{R}$ into $\vec{F} = \frac{k q 1 q 2}{R^{2}} \cdot \hat{R}$ ?