-normal-the-field-is-vec-e12xlhat-ztextnc-what-is-the-flux-through-the-rectangle

Question

A rectangle has length L=3.0L=3.0 m and width W=2.0W=2.0 m, lying in the xyxy-plane with an upward normal vector. The electric field is E⃗=(12xL)z^\displaystyle\vec{E}=\left(\frac{12x}{L}\right)\hat{z} N/C. Determine the electric flux through the rectangle.

Accepted Answer

36 N⋅m2/C36 	ext{ N}\cdot	ext{m}^2/	ext{C}

Answer

72 N⋅m2/C72	ext{ N}\cdot	ext{m}^2/	ext{C}

Answer

18 N⋅m2/C18	ext{ N}\cdot	ext{m}^2/	ext{C}

Answer

24 N⋅m2/C24	ext{ N}\cdot	ext{m}^2/	ext{C}

A rectangle has length L=3.0L=3.0 m and width W=2.0W=2.0 m, lying in the xyxy-plane with an upward normal vector. The electric field is E⃗=(12xL)z^\(\displaystyle\[\vec{E}\)=\(\left\)(\(\frac{12x}{L}\]\right\))\(\hat{z}\) N/C. Determine the electric flux through the rectangle.

A rectangle has length $L equals 3.0$ m and width $W equals 2.0$ m, lying in the $x y$ -plane with an upward normal vector. The electric field is $\vec{E} = (\frac{12 x}{L}) \hat{z}$ N/C. Determine the electric flux through the rectangle.