tential-energy-ux-5x4-2x3-7-j-where-x-is-in-meters-what-is-the-force-function-fx

Question

A particle moves in one dimension with potential energy U(x)=(5x4−2x3+7)U(x)=\$$left(5x^4$-2x^3+7$$\right) J, where xx  is in meters. What is the force function F(x)F(x)?

Accepted Answer

−$$20x3+6x2-20x^3$$ + $$6x^2$$

Answer

20x3−$$6x220x^3$$ - $$6x^2$$

Answer

−$$15x3+4x2-15x^3$$ + $$4x^2$$

Answer

−$$20x4+6x3-20x^4$$ + $$6x^3$$

A particle moves in one dimension with potential energy U(x)=(5x4−2x3+7)U(x)=\(\left\)(5x^4-2x^3+7\(\right\)) J, where xx is in meters. What is the force function F(x)F(x)?

A particle moves in one dimension with potential energy $U (x) = (5 x^{4} - 2 x^{3} + 7)$ J, where $x$ is in meters. What is the force function $F (x)$ ?