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Finding the Density of Charge Carriers in a Liquid-Filled Pipe

Study Guide - Smart Notes

Tailored notes based on your materials, expanded with key definitions, examples, and context.

Q1. A liquid-filled pipe contains Ca2+ ions (each ion has a net charge of +2e, where e = 1.6 × 10-19 C) and has a radius of 2.00 mm. When the current flowing along the pipe is 3.14 × 10-4 A, the carrier drift velocity is 5.00 × 10-5 m/s. What is the density of Ca2+ ions in the liquid-filled pipe?

Background

Topic: Current and Drift Speed

This question tests your understanding of how electric current relates to the density of charge carriers, their charge, drift velocity, and the cross-sectional area of the conductor. It is a classic application of the formula for current in terms of microscopic properties.

Key Terms and Formulas

  • Current (): The rate of flow of charge.

  • Charge carrier density (): Number of charge carriers per unit volume.

  • Drift velocity (): Average velocity of charge carriers due to an electric field.

  • Charge of carrier (): For Ca2+, .

  • Cross-sectional area (): For a pipe of radius , .

Key formula:

Current and drift speed questionDiagram showing positive charge carriers moving with drift velocity

Step-by-Step Guidance

  1. Identify the known values: A, mm m, m/s, C.

  2. Calculate the cross-sectional area of the pipe: .

  3. Write the formula for current in terms of charge carrier density: .

  4. Rearrange the formula to solve for : .

  5. Plug in the values for , , , and to set up the calculation for . Do not compute the final value yet.

Try solving on your own before revealing the answer!

Final Answer: m-3

m2 C m-3

This is the density of Ca2+ ions in the pipe, found by relating the macroscopic current to the microscopic properties of the charge carriers.

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