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Solubilty Product Constant
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Solubilty Product Constant
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6. Chemical Equilibrium / Solubilty Product Constant / Problem 2
Problem 2
Given the molar solubility of calcium fluoride (CaF
2
) is 2.14 x 10
-4
M, calculate its K
sp
.
A
4.91 x 10
-11
B
2.14 x 10
-4
C
1.07 x 10
-10
D
3.91 x 10
-11
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