for-x-14-y-22-1-determine-the-focus-and-directrix-of-the-horizontal-parabola

Question

For the horizontal parabola x=−14(y−2)2+1\displaystyle x=-\frac{1}{4}$$(y-2)^2+1$$, determine the coordinates of the focus and the equation of the directrix.

Accepted Answer

Focus: (0,2)(0, 2) Directrix: x=2x = 2

Answer

Focus: (2,0)(2, 0) Directrix: y=2y = 2

Answer

Focus: (1,1)(1, 1) Directrix: x=2x = 2

Answer

Focus: (0,2)(0, 2) Directrix: x=−2x = −2

For the horizontal parabola x=−14(y−2)2+1\(\displaystyle\) x=-\(\frac{1}{4}\)(y-2)^2+1, determine the coordinates of the focus and the equation of the directrix.

For the horizontal parabola $x = - \frac{1}{4} (y - 2)^{2} + 1$ , determine the coordinates of the focus and the equation of the directrix.