Beginning & Intermediate Algebra
4x2+36y2=1444x^2 + 36y^2 = 144
x24+y236=1\(\frac{x^2}{4}\)+\(\frac{y^2}{36}\)=1
x216+y29=1\(\frac{x^2}{16}\)+\(\frac{y^2}{9}\)=1
x236+y24=1\(\frac{x^2}{36}\)+\(\frac{y^2}{4}\)=1