let-pg05pg05phg04pg05pgprime05phg04-and-phg01phgprime01-what-is-pgh-pgh-accordin

Question

Let P(G)=0.5,P(G′)=0.5,P(H∣G)=0.4,P(G)=0.5,$$P(G^{\prime})=0.5$$,P(H|G)=0.4, and P(H∣G′)=0.1P(H|$$G^{\prime})=0.1. $$What is P(G∣H) P(G|H)  according to Bayes’ Theorem?

Accepted Answer

45\frac45

Answer

23\frac23

Answer

711\frac{7}{11}

Answer

411\frac{4}{11}

Let P(G)=0.5,P(G′)=0.5,P(H∣G)=0.4,P(G)=0.5,P(G^{\(\prime\)})=0.5,P(H|G)=0.4, and P(H∣G′)=0.1P(H|G^{\(\prime\)})=0.1. What is P(G∣H) P(G|H) according to Bayes’ Theorem?

Let $P (G) = 0.5, P (G^{'}) = 0.5, P (H ∣ G) = 0.4,$ and $P of open paren H divides G prime close paren equals 0.1$ . What is $P (G ∣ H)$ according to Bayes’ Theorem?