Without actually graphing, identify the type of graph that each equation has.

$\frac{x^2}{4}-\frac{y^2}{16}=1$

Without actually graphing, identify the type of graph that each equation has.

$\frac{\left(x+3\right)^2}{16}+\frac{\left(y-2\right)^2}{16}=1$

Identify and sketch the graph of each relation.

$3x^2+6x+3y^2-12y=12$