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17. Acid and Base Equilibrium - Part 3 of 4
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Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
17. Acid and Base Equilibrium - Part 3 of 4
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17. Acid and Base Equilibrium / Triprotic Acids and Bases / Problem 8
Problem 8
Citric acid (HOC(CO
2
H)(CH
2
CO
2
H)
2
) is a weak triprotic acid. Write balanced dissociation equations and corresponding equilibrium expressions for each dissociation step.
A
First Dissociation
HOC(COOH)(CH
2
COOH)
2
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + HOC(COO)(CH
2
COOH)
2
−
(aq)
K
a1
= [H
3
O
+
][HOC(COO)(CH
2
COOH)
2
−
]/[HOC(COOH)(CH
2
COOH)
2
]
Second dissociation
HOC(COO)(CH
2
COOH)
2
−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq)
K
a2
= [H
3
O
+
][HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]/[HOC(COO)(CH
2
COOH)
2
−
]
Third dissociation
[HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)
2
]
3−
(aq)
K
a3
= [H
3
O
+
][HOC(COO)(CH
2
COO)
2
]
3−
]/[HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]
B
First Dissociation
HOC(COOH)(CH
2
COOH)
2
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + HOC(COO)(CH
2
COOH)
2
2−
(aq)
K
a1
= [H
3
O
+
][HOC(COO)(CH
2
COOH)
2
2−
]/[HOC(COOH)(CH
2
COOH)
2
]
Second dissociation
HOC(COO)(CH
2
COOH)
2
−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq)
K
a2
= [H
3
O
+
][HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]/[HOC(COO)(CH
2
COOH)
2
−
]
Third dissociation
[HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)
2
]
3−
(aq)
K
a3
= [H
3
O
+
][HOC(COO)(CH
2
COO)
2
]
3−
]/[HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]
C
First Dissociation
HOC(COOH)(CH
2
COOH)
2
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + HOC(COO)(CH
2
COOH)
2
−
(aq)
K
a1
= [H
3
O
+
][HOC(COO)(CH
2
COOH)
2
−
]/[HOC(COOH)(CH
2
COOH)
2
]
Second dissociation
HOC(COO)(CH
2
COOH)
2
−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq)
K
a2
= [H
3
O
+
][HOC(COO)(CH
2
COOH)
2
−
]/[HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]
Third dissociation
[HOC(COO)(CH
2
COO)(CH
2
COOH)]
2
−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)
2
]
3−
(aq)
K
a3
= [H
3
O
+
][HOC(COO)(CH
2
COO)
2
]
3−
]/[HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]
D
First Dissociation
HOC(COOH)(CH
2
COOH)
2
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + HOC(COO)(CH
2
COOH)
2
−
(aq)
K
a1
= [H
3
O
+
][HOC(COO)(CH
2
COOH)
2
−
]/[HOC(COOH)(CH
2
COOH)
2
]
Second dissociation
HOC(COO)(CH
2
COOH)
2
−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq)
K
a2
= [H
3
O
+
][HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]/[HOC(COO)(CH
2
COOH)
2
−
]
Third dissociation
[HOC(COO)(CH
2
COO)(CH
2
COOH)]
2−
(aq) + H
2
O(l) ⇌ H
3
O
+
(aq) + [HOC(COO)(CH
2
COO)
2
]
3−
(aq)
K
a3
= [H
3
O
+
][HOC(COO)(CH
2
COO)(CH
2
COOH)
2−
]/[HOC(COO)(CH
2
COO)
2
]
3−
]
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