given-the-two-reactions-h2s-hs-h-k1-9-56-x-10-8-and-hs-s2-h-k2-1-44-x-10-19what-

Question

The dissociation of hydrogen selenide (H₂Se) takes place in two steps:

H₂Se ⇌ H⁺ + HSe^- K₁ = 1.29×10^-4

HSe^- ⇌ H⁺ + Se²^- K₂ = 1.00×10^-11

Calculate the equilibrium constant for the following reaction:

Se^2- + 2H⁺ ⇌ H₂Se

Accepted Answer

7.75×10¹⁴

Answer

1.29×10^-15

Answer

1.29×10⁷

Answer

6.45×10^-16

The dissociation of hydrogen selenide (H2Se) takes place in two steps:H2Se ⇌ H+ + HSe- K1 = 1.29×10-4HSe- ⇌ H+ + Se2- K2 = 1.00×10-11Calculate the equilibrium constant for the following reaction:Se2- + 2H+ ⇌ H2Se