a-voltaic-cell-initially-consists-of-a-0-0250-m-mg-mg2-half-cell-and-a-1-32-m-ag-1

Question

A voltaic cell initially consists of a 0.0250 M Mg/Mg²⁺ half-cell and a 1.32 M Ag/Ag⁺ half-cell. Calculate the cell potential when the Ag⁺has already dropped to 3.18 V.

Accepted Answer

[Mg²⁺] = 0.289 M, [Ag⁺] = 0.792 M

Answer

[Mg²⁺] = 0.189 M, [Ag⁺] = 0.591 M

Answer

[Mg²⁺] = 0.239 M, [Ag⁺] = 0.722 M

Answer

[Mg²⁺] = 0.164 M, [Ag⁺] = 0.697 M

A voltaic cell initially consists of a 0.0250 M Mg/Mg2+ half-cell and a 1.32 M Ag/Ag+ half-cell. Calculate the cell potential when the Ag+ has already dropped to 3.18 V.

A voltaic cell initially consists of a 0.0250 M Mg/Mg²⁺ half-cell and a 1.32 M Ag/Ag⁺ half-cell. Calculate the cell potential when the Ag⁺has already dropped to 3.18 V.