consider-the-ligand-12-bisdiphenylphosphinoethane-ph2pch2ch2pph2-or-dppei-provid

Question

Consider the ligand dimethoxyethane [CH₃OCH₂CH₂OCH₃] or DME.

i. Provide the Lewis structure of DME. How is it similar to ethylenediamine as a ligand?

ii. Determine the oxidation state of Nb in K₂[NbCl₂(CO)₂(DME)].

iii. Draw the structure [NbCl₂(CO)₂(DME)]^2–, include isomers if applicable.

Accepted Answer

i.

Lewis structure of dimethoxyethane (DME) showing its bidentate nature.

ii. Dimethoxyethane and ethylenediamine are both bidentate ligands. However, dimethoxyethane will mostly be lower in the spectrochemical series than dimethylamine.

iii.

Structures of [NbCl2(CO)2(DME)]2– showing possible isomers.

Answer

i.

Lewis structure of dimethoxyethane (DME) showing its bidentate nature.

ii. Dimethoxyethane and ethylenediamine are both bidentate ligands. However, dimethoxyethane will mostly be higher in the spectrochemical series than dimethylamine.

iii.

Structures of [NbCl2(CO)2(DME)]2– showing possible isomers.

Answer

i.

Lewis structure of dimethoxyethane (DME) showing its bidentate nature.

ii. Dimethoxyethane and ethylenediamine are both bidentate ligands. However, dimethoxyethane will mostly be lower in the spectrochemical series than dimethylamine.

iii.

Structures of [NbCl2(CO)2(DME)]2– showing possible isomers.

Answer

i.

Lewis structure of dimethoxyethane (DME) showing its bidentate nature.

ii. Dimethoxyethane and ethylenediamine are both bidentate ligands. However, dimethoxyethane will mostly be higher in the spectrochemical series than dimethylamine.

iii.

Structures of [NbCl2(CO)2(DME)]2– showing possible isomers.

Consider the ligand dimethoxyethane [CH3OCH2CH2OCH3] or DME.i. Provide the Lewis structure of DME. How is it similar to ethylenediamine as a ligand?ii. Determine the oxidation state of Nb in K2[NbCl2(CO)2(DME)].iii. Draw the structure [NbCl2(CO)2(DME)]2–, include isomers if applicable.