Using the thermodynamic data below calculate the ΔS°_rxn for the following reaction and justify the change in entropy.
CO(g) + NH₃(g) → HCN(g) + H₂O(g)

• A. ΔS°_rxn = +0.1 J/mol; The change in entropy is very small because the moles of gas in the reaction are the same.
• B. ΔS°_rxn = +6.1 J/mol; The change in entropy is very small because the moles of gas in the reaction are the same.
• C. ΔS°_rxn = –0.1 J/mol; The change in entropy is very small because the size and shape of the species in the reaction are the same.
• D. ΔS°_rxn = –6.1 J/mol; The change in entropy is very small because the size and shape of the species in the reaction are the same.
• E. ΔS°_rxn = +0.1 J/mol; The change in entropy is very small because the size and shape of the species in the reaction are the same.
• F. ΔS°_rxn = –6.1 J/mol; The change in entropy is very small because the moles of gas in the reaction are the same.

Answer: (A)