identify-the-sign-of-ssys-and-ssurr-for-the-reaction-below-without-doing-calcula

Question

Identify the sign of ΔS_sys and ΔS_surr for the reaction below without doing calculations and identify which temperature condition in which the reaction would be spontaneous

2 C₆H₆(l) + 15 O₂(g) → 12 CO₂(g) + 6 H₂O(l) ΔH°_rxn = -6534 kJ

Accepted Answer

ΔSsys: (-), ΔSsurr: (+), spontaneous only at low temperatures

Answer

ΔSsys: (+), ΔSsurr: (+), non-spontaneous only at all temperatures

Answer

ΔSsys: (+), ΔSsurr: (+), spontaneous only at hight temperatures

Answer

ΔSsys: (-), ΔSsurr: (-), spontaneous only at all temperatures

Identify the sign of ΔSsys and ΔSsurr for the reaction below without doing calculations and identify which temperature condition in which the reaction would be spontaneous2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) ΔH°rxn = -6534 kJ

Identify the sign of ΔS_sys and ΔS_surr for the reaction below without doing calculations and identify which temperature condition in which the reaction would be spontaneous
2 C₆H₆(l) + 15 O₂(g) → 12 CO₂(g) + 6 H₂O(l) ΔH°_rxn = -6534 kJ