the-reaction-h2-g-i2-g-2-hi-g-was-thought-to-occur-via-a-two-step-mechanism-i2-g

Question

The reaction H₂(g) + I₂(g) → 2 HI(g) was thought to occur via a two-step mechanism:

Step 1: I₂(g) ⇌ 2 I(g) (fast equilibrium)
Step 2: 2 I(g) + H₂(g) → 2 HI(g) (slow)

Determine the rate law for the reaction.

Accepted Answer

Rate = k[I₂][H₂]

Answer

Rate = k[I₂][H₂]²

Answer

Rate = k[I]²[H₂]

Answer

Rate = k[I₂]²[H₂]

The reaction H2(g) + I2(g) → 2 HI(g) was thought to occur via a two-step mechanism:Step 1: I2(g) ⇌ 2 I(g) (fast equilibrium)Step 2: 2 I(g) + H2(g) → 2 HI(g) (slow)Determine the rate law for the reaction.