Midterm 1 Practice Exam – General Chemistry Study Guidance

Q4. As the wavelength of electromagnetic radiation decreases, which quantity increases?

Background

Topic: Electromagnetic Radiation and Wave Properties

This question tests your understanding of the relationship between wavelength, frequency, and other properties of electromagnetic waves.

Key Terms and Formulas:

• Wavelength ($\lambda$): The distance between two consecutive peaks of a wave.

• Frequency ($\nu$): The number of wave cycles that pass a given point per second.

• Speed of light ($c$): $c = 2.998 \times 10^8$ m/s

• Relationship: $c = \lambda \nu$

Step-by-Step Guidance

1. Recall the formula relating wavelength and frequency: $c = \lambda \nu$, where $c$ is the speed of light, $\lambda$ is wavelength, and $\nu$ is frequency.

2. Notice that $c$ is constant, so as $\lambda$ decreases, $\nu$ must increase to keep the product constant.

3. Consider other properties (such as energy) that depend on frequency and wavelength. For example, energy of a photon: $E = h \nu$.

Try solving on your own before revealing the answer!

Final Answer: Frequency increases as wavelength decreases.

Since $c = \lambda \nu$, a decrease in wavelength means an increase in frequency. Energy also increases with frequency.