The hydrogenation of pyridine (C₅H₅N) produces piperidine (C₅H₁₀NH). The actual yield of the reaction below is 83.0%. Calculate the mass of pyridine in grams produced from 42.5 g of pyridine (MW piperidine = 85.148 amu; MW pyridine = 79.1 amu).

Consider the following reaction: 

2 Sb(s) + 3 S(s) → Sb₂S₃(s)

Calculate the percent yield of the reaction of 4.63 g of Sb(s) in excess S(s) if 2.31 g of Sb₂S₃ was actually produced. 

Consider the reaction below: 

2 NH₃ + OCl^- → N₂H₄ + Cl^- + H₂O

Calculate the moles of N₂H₄ as produced if 6.93 mol of NH₃ reacted and the reaction has a 85.6% yield

Consider the following reaction: 

4C₆H₅Cl + SiCl₄ + 8Na → (C₆H₅)₄Si + 8NaCl

Calculate the mass of C₆H₅Cl that will be required to make 163.2 g of (C₆H₅)₄Si if the reaction has a 91.1 % yield.