Consider the following reaction: 
2 Sb(s) + 3 S(s) → Sb₂S₃(s)
Calculate the percent yield of the reaction of 4.63 g of Sb(s) in excess S(s) if 2.31 g of Sb₂S₃ was actually produced. 

• A. 95.1 %
• B. 61.2 %
• C. 47.3 %
• D. 35.8 %

Answer: (D)