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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.2.18a

17–20. Increasing and decreasing solutions Consider the following differential equations. A detailed direction field is not needed.


a. Find the solutions that are constant, for all t ≥ 0 (the equilibrium solutions).


y'(t) = (y−2)(y+1)

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Identify the equilibrium solutions by setting the derivative equal to zero: \(y'(t) = 0\).
Set the right-hand side of the differential equation equal to zero: \((y - 2)(y + 1) = 0\).
Solve the equation \((y - 2)(y + 1) = 0\) for \(y\) to find the constant solutions.
The solutions to this equation give the equilibrium solutions where \(y(t)\) does not change over time.
Write the equilibrium solutions explicitly as \(y(t) = 2\) and \(y(t) = -1\) for all \(t \geq 0\).

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Equilibrium Solutions of Differential Equations

Equilibrium solutions occur when the derivative y'(t) equals zero for all t, meaning the solution y(t) remains constant over time. To find these, set the right-hand side of the differential equation to zero and solve for y. These solutions represent steady states where the system does not change.
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Solutions to Basic Differential Equations

Factoring and Solving Polynomial Equations

To find equilibrium points in y'(t) = (y−2)(y+1), factor the expression and set each factor equal to zero. This yields values of y that make the derivative zero. Understanding how to factor and solve polynomial equations is essential for identifying these constant solutions.
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Solving Logarithmic Equations

Interpretation of Differential Equations Without Direction Fields

Even without a direction field, analyzing the sign of y'(t) around equilibrium points helps determine whether solutions increase or decrease. This qualitative analysis aids in understanding the behavior of solutions near equilibrium without graphing, focusing on algebraic manipulation and sign analysis.
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Determining Differentiability Without A Graph
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43–44. Motion in a gravitational field: An object is fired vertically upward with initial velocity v(0)=v₀ from initial position s(0)=s₀.

a. For the following values of v₀ and s₀, find the position and velocity functions for all times at which the object is above the ground (s = 0).

v₀ = 49 m/s, s₀ = 60 m

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Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

a. The general solution of the differential equation y'(t) = 1 is y(t) = t

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[Use of Tech] Analysis of a separable equation Consider the differential equation yy'(t) = ½eᵗ + t and carry out the following analysis.

a. Find the general solution of the equation and express it explicitly as a function of t in two cases: y > 0 and y < 0.

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{Use of Tech} Torricelli’s law An open cylindrical tank initially filled with water drains through a hole in the bottom of the tank according to Torricelli’s law (see figure). If h(t) is the depth of water in the tank for t≥0 s, then Torricelli’s law implies h′(t)=−k√h, where k is a constant that includes g=9.8m/s², the radius of the tank, and the radius of the drain. Assume the initial depth of the water is h(0)=Hm. 

a. Find the solution of the initial value problem.

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33–36. {Use of Tech} Computing Euler approximations Use a calculator or computer program to carry out the following steps.

a. Approximate the value of y(T) using Euler’s method with the given time step on the interval [0,T].


y′(t) = -2y, y(0) = 1; Δt = 0.2, T = 2; y(t) = e⁻²ᵗ

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38–43. Equilibrium solutions A differential equation of the form y′(t)=f(y) is said to be autonomous (the function f depends only on y). The constant function y=y0 is an equilibrium solution of the equation provided f(y0)=0 (because then y'(t)=0 and the solution remains constant for all t). Note that equilibrium solutions correspond to horizontal lines in the direction field. Note also that for autonomous equations, the direction field is independent of t. Carry out the following analysis on the given equations.

a. Find the equilibrium solutions.


y′(t) = 2y + 4

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