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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoHass 15th EditionCh. 7 - Transcendental FunctionsProblema 7.1.68b
Capitolo 7, Problema 7.1.68b

In Exercises 67–72, you will explore some functions and their inverses together with their derivatives and tangent line approximations at specified points. Perform the following steps using your CAS:


b. Solve the equation y=f(x) for x as a function of y, and name the resulting inverse function g.


68. y= (3x+2)/(2x-11), -2 ≤ x ≤ 2, x_0=1/2

Guida verificata passo dopo passo
1
Start with the given function: \(y = \frac{3x + 2}{2x - 11}\), where \(-2 \leq x \leq 2\).
To find the inverse function \(g(y)\), first solve the equation \(y = \frac{3x + 2}{2x - 11}\) for \(x\) in terms of \(y\).
Multiply both sides of the equation by the denominator \((2x - 11)\) to eliminate the fraction: \(y(2x - 11) = 3x + 2\).
Distribute \(y\) on the left side: \(2xy - 11y = 3x + 2\).
Group all terms involving \(x\) on one side and constants on the other: \(2xy - 3x = 11y + 2\). Then factor out \(x\): \(x(2y - 3) = 11y + 2\). Finally, solve for \(x\): \(x = \frac{11y + 2}{2y - 3}\). This expression defines the inverse function \(g(y)\).

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Inverse Functions

An inverse function reverses the effect of the original function, swapping inputs and outputs. For a function f(x), its inverse g(y) satisfies g(f(x)) = x. Finding the inverse involves solving y = f(x) for x in terms of y, which is essential for understanding how to express x as a function of y.
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Domain and Range Restrictions

When finding inverses, it is crucial to consider the domain and range of the original function to ensure the inverse is well-defined and one-to-one. Restricting the domain, as in -2 ≤ x ≤ 2, helps avoid ambiguity and guarantees the inverse function exists and behaves properly over that interval.
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Finding the Domain and Range of a Graph

Derivative and Tangent Line Approximation

The derivative of a function at a point gives the slope of the tangent line there, which can be used for linear approximations. Understanding how to compute derivatives of both the function and its inverse is key to analyzing behavior near specified points, such as x₀ = 1/2, and for approximating values.
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