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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 27

Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. (3x+1)/3 - 13/2 = (1-x)/4

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Start by writing down the given equation: \(\frac{3x+1}{3} - \frac{13}{2} = \frac{1 - x}{4}\).
To eliminate the fractions, find the least common denominator (LCD) of 3, 2, and 4, which is 12. Multiply every term on both sides of the equation by 12 to clear the denominators.
Distribute 12 to each term: \(12 \times \frac{3x+1}{3} - 12 \times \frac{13}{2} = 12 \times \frac{1 - x}{4}\).
Simplify each term after multiplication: \(4(3x+1) - 6(13) = 3(1 - x)\).
Now, expand the parentheses and solve the resulting linear equation for \(x\). After finding \(x\), check if the solution satisfies the original equation to determine if it is an identity, conditional, or inconsistent equation.

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Solving linear equations involves isolating the variable on one side to find its value. This often requires clearing fractions by finding a common denominator or multiplying both sides by the least common multiple. Understanding how to manipulate equations step-by-step is essential to find the solution accurately.
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An identity is true for all values of the variable, a conditional equation is true for specific values, and an inconsistent equation has no solution. Recognizing these types helps interpret the solution set after solving the equation, indicating whether the equation holds universally, sometimes, or never.
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