Skip to main content
Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 27

The length of the rectangular tennis court at Wimbledon is 6 feet longer than twice the width. If the court's perimeter is 228 feet, what are the court's dimensions?

Guida verificata passo dopo passo
1
Define variables for the dimensions of the tennis court: let the width be \(w\) feet, and the length be \(l\) feet.
Express the length in terms of the width using the given relationship: \(l = 2w + 6\).
Recall the formula for the perimeter of a rectangle: \(P = 2l + 2w\). Substitute the given perimeter value: \(228 = 2l + 2w\).
Substitute the expression for \(l\) from step 2 into the perimeter equation: \(228 = 2(2w + 6) + 2w\).
Simplify and solve the resulting equation for \(w\), then use the value of \(w\) to find \(l\) using \(l = 2w + 6\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
4m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Formulating Algebraic Expressions from Word Problems

This involves translating verbal descriptions into mathematical expressions or equations. For example, 'the length is 6 feet longer than twice the width' can be written as L = 2W + 6, where L is length and W is width.
Video consigliato:
05:09
Introduction to Algebraic Expressions

Perimeter of a Rectangle

The perimeter of a rectangle is the total distance around it, calculated as P = 2(L + W), where L is length and W is width. This formula helps relate the dimensions to the given perimeter value.

Solving Linear Equations

Once the problem is expressed as an equation, solving linear equations involves isolating variables to find their values. This includes combining like terms and using inverse operations to solve for unknowns.
Video consigliato:
04:02
Solving Linear Equations with Fractions