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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 51

Solve each equation in Exercises 47–64 by completing the square. x2−6x−11=0x^2 - 6x - 11 = 0

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1
Start with the given quadratic equation: \(x^2 - 6x - 11 = 0\).
Move the constant term to the other side to isolate the \(x\) terms: \(x^2 - 6x = 11\).
To complete the square, take half of the coefficient of \(x\), which is \(-6\), divide by 2 to get \(-3\), then square it to get \((-3)^2 = 9\).
Add this square (9) to both sides of the equation to maintain equality: \(x^2 - 6x + 9 = 11 + 9\).
Rewrite the left side as a perfect square trinomial: \((x - 3)^2 = 20\).

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