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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 75

Solve each equation by the method of your choice. 3x2−7x+1=03x^2-7x+1 =0

Guida verificata passo dopo passo
1
Identify the given quadratic equation: \(3x^2 - 7x + 1 = 0\).
Recall that a quadratic equation in the form $ax^2 + bx + c = 0$ can be solved using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Substitute the coefficients from the equation into the quadratic formula: \(a = 3\), \(b = -7\), and \(c = 1\), so the formula becomes \(x = \frac{-(-7) \pm \sqrt{(-7)^2 - 4 \cdot 3 \cdot 1}}{2 \cdot 3}\).
Simplify inside the square root (the discriminant): calculate \(b^2 - 4ac = (-7)^2 - 4 \cdot 3 \cdot 1\).
Evaluate the expression under the square root and then compute the two possible values for \(x\) by applying the plus and minus signs in the quadratic formula.

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Quadratic Equations

A quadratic equation is a second-degree polynomial equation in the form ax² + bx + c = 0, where a ≠ 0. It represents a parabola when graphed and typically has two solutions, which can be real or complex numbers.
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Quadratic Formula

The quadratic formula x = (-b ± √(b² - 4ac)) / (2a) provides a method to find the roots of any quadratic equation. It is especially useful when factoring is difficult or impossible, and the discriminant (b² - 4ac) determines the nature of the roots.
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